Malloc doubt

[guillermoh]

Hello everyone.

I have a little doubt about freeing allocated memory. I'm using this two functions.

gchar* status_code (gchar *status)
{
	gchar* data = "";
	
	status ++;		
	while (*status != CR && *(status+1) != LF)
	{
		data = concatenar_char(data,status);
		status ++;		
	}

	return data;
}/*status_code*/

gchar * concatenar_char (gchar* str1, gchar* str2)
{
	gchar *result;
	if ( str2 != NULL )
	{
		result = (gchar *)malloc(strlen(str1) + sizeof(gchar) + 1);
		if ( result != NULL )
		{
			strcpy(result, str1);
			strncat(result, str2, 1);
		}
	}
	return result;
}/*concatenar_char*/

In the second function I cant free result before return it. So where can I free the allocated memory (result) without getting an error from the compiler??

Is there a better way to do this?

Thanks in advance.

[robwhit]

So where can I free the allocated memory (result) without getting an error from the compiler??

anywhere after you call concatenar_char. in main, for example.

what's the error?

what's LF?

[ssharish2005]

It wont make any sense if you free the result before you return result in the function. The main idea in that function is to concatenate two string and return the result string. If you free of the string in the function itself, you cant retrieve any results from the calling function.

ssharish

[prog-bman]

result = (gchar *)malloc(strlen(str1) + sizeof(gchar) + 1);

Looks suspicious to me. Maybe?

result = malloc(strlen(str1) + strlen(str2) + 1);

[cpjust]

Here's my answer: http://www.tek-tips.com/viewthread.c...1406601&page=1